Pgmpietoncracklang++
From Esolang

P5
# PROLAN/M SUM.PRM by Keymaker
5 1
4
0+0=?
0+0=?
P5
# PROLAN/M SUM.PRM by Keymaker (0,0) RESULT
23 40
255
1  0+0*=
 25  0+*A.=
 13  0+*A=.
 24  0+*A=0
 35  0*P...........A=0
  2  0*P..........A.=0
  2  0*P.........A..=0
  2  0*P........A...=0
  2  0*P.......A....=0
  2  0*P......A.....=0
  2  0*P.....A......=0
  2  0*P....A.......=0
  2  0*P...A........=0
  2  0*P..A.........=0
  2  0*P.A..........=0
  2  0*PA...........=0
 13  0*PA..........=.0
 13  0*PA.........=..0
 13  0*PA........=...0
 13  0*PA.......=....0
 13  0*PA......=.....0
 13  0*PA.....=......0
 13  0*PA....=.......0
 13  0*PA...=........0
 13  0*PA..=.........0
 13  0*PA.=..........0
 13  0*PA=...........0
 14  0*PA=#0
 25  *A.PA=#0
 12  *AP.A=#0
  2  *APA.=#0
 13  *APA=.#0
 24  *APA=0#0
 39  *APA=0_#
 37  *APA=0#
 61  APA=0#
 62  APA=0
 63  0PA=0
 63  0P0=0
 73  0+0=0
P5
# XKCD Random number
5 1
4
0+0=?
XKCD Random Number
P3
# //chosen by fair dice roll.;\n guaranteed to be random.//
4 4
4
  0   4   0   4 
  0   4   0   4 
  0   4   4   4 
  0   0   0   4 
  0   0   0   4 

Interpreter sketch

Meta-interpreter: https://raw.githubusercontent.com/iannmiui-png/Pgmpietoncracklangplus/refs/heads/main/pgmpietoncracklang_plus.py Pgmpietoncracklang+

P5
# Pgmpietoncracklang+
203 89
255
import sys,re
def main():
 d=open(0,encoding='l1').read().split('\n');c=d[1];v=int(d[3].split()[0])
 if'XKCD'in c:print('P3\n# //chosen by fair dice roll.;\\n guaranteed to be random.//\n4 4\n%d'%v+''.join('\n'+''.join('%3d '%(v*int(x))for x in r)for r in'0101 0101 0111 0001 0001'.split()));sys.exit()
 m=re.search(r'\((\d+),(\d+)\)',c);s=m.expand(r'\1+\2=?')if m else'\n'.join(d[4:]).strip()
 R=[l[1:-1].partition(',')for l in P.split('\n')if l];T=[]
 while 1:
  for i,(a,_,b)in enumerate(R):
   j=s.find(a)
   if j>=0:break
  if a=='':break
  s=s[:j]+b+s[j+len(a):];T+=['%4d  %s'%(i,s)]
 w=max(map(len,T));print('P5\n%s RESULT\n%d %d\n%d\n'%(c,w,len(T),v)+''.join(t.ljust(w)for t in T),end='')
P=r"""($,  PROLAN/M sum program, written by Keymaker  )
(=?,*=)
(.A,A.)
(.B,B.)
(.C,C.)
(.D,D.)
(.E,E.)
(.F,F.)
(.G,G.)
(.H,H.)
(.I,I.)
(.J,J.)
(.P,P.)
(.=,=.)
(=...........,=#)
(=..........,=9)
(=.........,=8)
(=........,=7)
(=.......,=6)
(=......,=5)
(=.....,=4)
(=....,=3)
(=...,=2)
(=..,=1)
(=.,=0)
(0*,*A.)
(1*,*B..)
(2*,*C...)
(3*,*D....)
(4*,*E.....)
(5*,*F......)
(6*,*G.......)
(7*,*H........)
(8*,*I.........)
(9*,*J..........)
(+*,*P...........)
(a_,_bbbbbbbbbb)
(_,)
(b,a)
(#0,_#)
(#1,_b#)
(#2,_bb#)
(#3,_bbb#)
(#4,_bbbb#)
(#5,_bbbbb#)
(#6,_bbbbbb#)
(#7,_bbbbbbb#)
(#8,_bbbbbbbb#)
(#9,_bbbbbbbbb#)
(=@,=1)
(0@,1)
(1@,2)
(2@,3)
(3@,4)
(4@,5)
(5@,6)
(6@,7)
(7@,8)
(8@,9)
(9@,@0)
(a,@)
(*,)
(#,)
(A,0)
(B,1)
(C,2)
(D,3)
(E,4)
(F,5)
(G,6)
(H,7)
(I,8)
(J,9)
(P,+)
(,)"""
main()

Directory

<-Pgmpietoncracklang
->Pgmpietoncracklang/Pgmpietoncracklang++

Pgmpietonracklang++

You can do Spoon by introducing delimiters. The delimiter is a gradient which differentiates the inner part of the strings rather than the edges.

brainfuck Spoon syntax Pgmpietonracklang++ syntax Description
+ 1 0\0\0\ Increment the memory cell at the pointer
- 000 0\123456789876543210\ Decrement the memory cell at the pointer
< 010 0\1234567898765432102345678987654321 Move the pointer to the left
> 011 0\0\1234567898765432102345678987654321 Move the pointer to the right
[ 0011 0\0\123456789876543210\0\ Jump past the matching ] if the cell at the pointer is 0
] 00100 0\0\123456789876543210\123456789876543210\ Jump back to the matching [ if the cell at the pointer is nonzero
. 001010 0\0\123456789876543210\12345678987654321023456789876543210\ Output the character signified by the cell at the pointer
, 0010110 0\0\123456789876543210\1234567898765432102345678987654321023456789876543210\ Input a character and store it in the cell at the pointer
00101110 /// 'print "\n",m,"\n";',
EOF 00101111 0\0\123456789876543210\12345678987654321023456789876543210234567898765432102345678987654321 Terminate program execution.

Pgmpietonracklang++///

This will be Slashes implemented in such a manner as the previous iterations. Miui (talk) 13:59, 1 September 2026 (UTC)